How it’s calculated
Grout fills a narrow prism around every tile. Per unit of tiled area, the joint length is (L + W) ÷ (L × W), so the grout volume is that length × joint width × joint depth. Multiply by the grout’s density for weight, then add waste.
Check against Sika’s data sheet: 30 × 30 cm tiles, 10 mm thick, 3 mm joints, 1.9 kg/L: (300 + 300) ÷ (300 × 300) × 3 × 10 × 1.9 = 0.38 kg/m², matching the published 380 g/m².
Example: 100 ft² of 12 × 12 in tile, 3/8 in thick, 1/8 in joints. Volume = 14,400 in² × (24 ÷ 144) × 0.125 × 0.375 = 112.5 in³ = 1.84 L. At 1.9 kg/L that is 3.50 kg (7.72 lb); with 10% waste 8.5 lb, so one 25 lb bag.
Frequently asked questions
How much grout do I need per square foot?
It depends on tile size and joint width. 12 × 12 in tile, 3/8 in thick with 1/8 in joints, uses about 0.08 lb per square foot; small mosaics with the same joints use several times more.
Sanded or unsanded grout?
Manufacturers generally recommend unsanded grout for joints of 1/8 in (3 mm) or less and sanded grout for wider joints. Follow the grout bag’s joint-width range.
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Sources
- SikaCeram-638 Tile Grout product data sheet (consumption table and formula) — Sika
- Tile Council of North America (installation and grout standards) — Tile Council of North America
- Prealgebra 2e, 9.6 Volume and Surface Area (rectangular solids) — OpenStax
Formulas are taken from the free public references above. Results are provided “as is” for informational and educational purposes only. See our disclaimer.
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