Pipe Pressure Drop Calculator

Friction pressure drop and head loss in a straight pipe using Darcy–Weisbach with the Swamee–Jain friction factor and a pipe roughness table.

Values for new pipe. Roughness grows with age, corrosion and scale.

Results

Friction pressure drop Δp
24.789
Head loss h_f
2.528
Average velocity
1.019
Reynolds number
50,828
Turbulent flow.
Darcy friction factor f
0.02389
Swamee–Jain
Relative roughness ε/D
0.00092

Estimate only. This tool is for informational and educational purposes. Results depend on your inputs and simplifying assumptions, and are not a substitute for professional engineering, design or financial advice. Always verify with a qualified professional and applicable codes before purchasing, building or making decisions.

How it’s calculated

The Darcy–Weisbach equation gives the frictional loss in a straight, full, circular pipe with steady, incompressible, fully developed flow. The friction factor comes from the Reynolds number and the relative roughness: 64/Re for laminar flow, and the explicit Swamee–Jain (1976) approximation of the Colebrook equation otherwise (within about 1% of Colebrook for 5,000 ≤ Re ≤ 10⁸ and 10⁻⁶ ≤ ε/D ≤ 10⁻²).

h_f = f (L/D) v² / (2g) Δp = ρ g h_f = f (L/D) ρ v² / 2 Re = ρ v D / μ Laminar (Re < 2300): f = 64 / Re Swamee–Jain: f = 0.25 / [log₁₀(ε/(3.7 D) + 5.74 / Re⁰·⁹)]²

Fittings, valves, entrances and elevation changes are not included; add them as minor losses (K·v²/2g) and static head separately.

Example: 2 L/s of 20 °C water in 100 m of 50 mm commercial steel pipe. v = 0.002 ÷ (π × 0.05²/4) = 1.019 m/s, Re = 1000 × 1.019 × 0.05 ÷ 0.001002 ≈ 50,800, ε/D = 0.046/50 = 0.00092, f ≈ 0.0239, h_f = 0.0239 × (100/0.05) × 1.019² ÷ (2 × 9.807) ≈ 2.53 m, so Δp ≈ 24.8 kPa (3.6 psi).

Material (new)ε (mm)
Drawn tubing0.0015
Commercial steel / wrought iron0.046
Asphalted cast iron0.12
Galvanized iron0.15
Cast iron0.26
Wood stave0.18 – 0.9
Concrete0.3 – 3.0
Riveted steel0.9 – 9.0

Frequently asked questions

What is the difference between head loss and pressure drop?

They are the same loss in different units: Δp = ρ·g·h_f. For water, 1 m of head ≈ 9.81 kPa and 1 ft ≈ 0.433 psi.

Why Swamee–Jain instead of Colebrook?

Colebrook is implicit and needs iteration. Swamee–Jain is explicit and agrees with it to about 1% across normal engineering ranges, well inside the uncertainty of pipe roughness itself.

Is this the Darcy or Fanning friction factor?

Darcy (Moody) friction factor. The Fanning factor is one quarter of it.

How do I include fittings?

Add K·v²/(2g) for each fitting, or convert fittings to an equivalent length and add it to L.

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Sources

Formulas are taken from the free public references above. Results are provided “as is” for informational and educational purposes only. See our disclaimer.

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