Series & Parallel Resistor Calculator

Combine up to four resistors in series or parallel to get the equivalent resistance in ohms.

Ω
Ω
Ω
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Ω
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Results

Equivalent resistance (parallel)
68.75 Ω
Resistors combined
2
Equivalent conductance
0.0145455 S

How it’s calculated

In series the same current flows through every resistor, so resistances add. In parallel every resistor sees the same voltage, so conductances (1/R) add and the total is always smaller than the smallest resistor.

Series: R = R1 + R2 + R3 + R4 Parallel: 1/R = 1/R1 + 1/R2 + 1/R3 + 1/R4

Example: 100 Ω and 220 Ω in parallel give 1 ÷ (1/100 + 1/220) = 22,000 ÷ 320 = 68.75 Ω. In series they give 320 Ω.

Frequently asked questions

What is the shortcut for two resistors in parallel?

Product over sum: R = R1 × R2 ÷ (R1 + R2). For 100 Ω and 220 Ω that is 22,000 ÷ 320 = 68.75 Ω.

What about identical resistors in parallel?

n identical resistors R in parallel give R ÷ n. Two 1 kΩ resistors in parallel make 500 Ω.

How do I handle a mixed series-parallel network?

Reduce it step by step: combine each parallel group to one equivalent, then add the series parts, and repeat.

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Sources

Formulas are taken from the free public references above. Results are provided “as is” for informational and educational purposes only. See our disclaimer.

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