How it’s calculated
A transformer is rated in kVA (apparent power). Ignoring the small losses, the same kVA flows in the primary and secondary, so current is inversely proportional to voltage: Is/Ip = Vp/Vs = Np/Ns. For three-phase, apparent power is √3 × line voltage × line current.
Example: a 75 kVA three-phase transformer, 480 V primary, 208Y/120 V secondary. Ip = 75,000 ÷ (1.732 × 480) = 90.2 A; Is = 75,000 ÷ (1.732 × 208) = 208.2 A. A 25 kVA single-phase 240 V secondary carries 25,000 ÷ 240 = 104.2 A.
Full-load current is the starting point for conductor and overcurrent device selection; the electrical code sets the actual percentages, conductor ampacity and protection rules.
Frequently asked questions
Why is the secondary current higher?
Power in equals power out (less small losses), so stepping voltage down by a factor steps current up by the same factor.
Does power factor change the current?
No, for a given kVA. Current depends on apparent power (kVA). Power factor only determines how much of that kVA is real power (kW).
What voltage should I use for 208Y/120 V?
Use the line-to-line voltage, 208 V, with the three-phase setting.
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Sources
- University Physics Vol. 2, 15.6 Transformers — OpenStax
- Electric Circuits II (Kuphaldt), 7.2 Three-phase Power Systems — Workforce LibreTexts
Formulas are taken from the free public references above. Results are provided “as is” for informational and educational purposes only. See our disclaimer.
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